For every 6 kJ/mol change in standard state free energy, there is a ~10-fold change in the ratio of the number of molecules of P to the number of molecules of S at equilibrium; for a particular equilibrium S <-> P, the standard state free energy = +18 kJ/
(10 points)
written by dr_g • topics: enzymes block unblock • thermodynamics block unblock • kinetics block unblock • pharmacy block unblock • biochemistry block unblock
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